相交可以用来查找匹配两个集合之间，像这样：

  //指定两个数组。
INT [] ARRAY1 = {1，2，3};
INT [] ARRAY2 = {2，3，4};
//调用相交扩展方法。
VAR相交= array1.Intersect（ARRAY2）;
//写路口画面。
的foreach（在相交int值）
{
    Console.WriteLine（值）; //输出：2，3
}
 

不过我想实现的是相反的，我想列出的是缺少项比较两个集合时：

  //指定两个数组。
INT [] ARRAY1 = {1，2，3};
INT [] ARRAY2 = {2，3，4};
//调用相交扩展方法。
VAR相交= array1.NonIntersect（ARRAY2）; //我做了NonIntersect方法
//写路口画面。
的foreach（在相交int值）
{
    Console.WriteLine（值）; //输出：4
}
 

解决方案

如前所述，如果你想获得4作为结果，你可以这样做：

  VAR nonintersect = array2.Except（ARRAY1）;
 

如果你想真正的无交集（还兼有1和4），那么这应该做的伎俩：

  VAR nonintersect = array1.Except（ARRAY2）.Union（array2.Except（ARRAY1））;
 

这不会是最高效的解决方案，但对于小名单这应该只是罚款。

Intersect can be used to find matches between two collections, like so:

// Assign two arrays.
int[] array1 = { 1, 2, 3 };
int[] array2 = { 2, 3, 4 };
// Call Intersect extension method.
var intersect = array1.Intersect(array2);
// Write intersection to screen.
foreach (int value in intersect)
{
    Console.WriteLine(value); // Output: 2, 3
}

However what I'd like to achieve is the opposite, I'd like to list the items that are missing when comparing two collections:

// Assign two arrays.
int[] array1 = { 1, 2, 3 };
int[] array2 = { 2, 3, 4 };
// Call Intersect extension method.
var intersect = array1.NonIntersect(array2); // I've made up the NonIntersect method
// Write intersection to screen.
foreach (int value in intersect)
{
    Console.WriteLine(value); // Output: 4
}

As stated, if you want to get 4 as the result, you can do like this:

var nonintersect = array2.Except(array1);

If you want the real non-intersection (also both 1 and 4), then this should do the trick:

var nonintersect = array1.Except(array2).Union( array2.Except(array1));

This will not be the most performant solution, but for small lists it should work just fine.