对于下面的数据表列，什么是让最小值和最大值的最快方法？

  AccountLevel
0
1
2
3
 

解决方案

  INT minAccountLevel = int.MaxValue;
INT maxAccountLevel = int.MinValue;
的foreach（在table.Rows的DataRow博士）
{
    INT accountLevel = dr.Field＆LT; INT＆GT;（AccountLevel）;
    minAccountLevel = Math.Min（minAccountLevel，accountLevel）;
    maxAccountLevel = Math.Max​​（maxAccountLevel，accountLevel）;
}
 

是的，这的确是最快的方法。用LINQ 最小和最大扩展将永远是慢，因为你必须重复两次。你可能使用Linq 总结，但语法是不会有太大prettier比这已经是了。

For the following datatable column, what is the fastest way to get the min and max values?

AccountLevel  
0  
1  
2  
3 

int minAccountLevel = int.MaxValue;
int maxAccountLevel = int.MinValue;
foreach (DataRow dr in table.Rows)
{
    int accountLevel = dr.Field<int>("AccountLevel");
    minAccountLevel = Math.Min(minAccountLevel, accountLevel);
    maxAccountLevel = Math.Max(maxAccountLevel, accountLevel);
}

Yes, this really is the fastest way. Using the Linq Min and Max extensions will always be slower because you have to iterate twice. You could potentially use Linq Aggregate, but the syntax isn't going to be much prettier than this already is.