当比较在C＃中的平等两个字符串，什么是InvariantCulture的和有序的比较有什么区别？

When comparing two strings in c# for equality, what is the difference between InvariantCulture and Ordinal comparison?

推荐答案

在InvariantCulture的设置使用标准设定的字符排序（A，B，C，...等）。这是相对于一些特定的区域设置，其可排序以不同的顺序字符（'一个与 - 急性'可以是之前的的或的后一，取决于区域设置，等等）。

The "InvariantCulture" setting uses a "standard" set of character orderings (a,b,c, ... etc.). This is in contrast to some specific locales, which may sort characters in different orders ('a-with-acute' may be before or after 'a', depending on the locale, and so on).

序号的比较，在另一方面，相貌纯粹在的原始字节（s）表示重新present字符的值。有一个很大的样品在http://msdn.microsoft.com/en-us/library/e6883c06.aspx显示的各种StringComparison值的结果。一路到了最后，这表明（摘录）：

"Ordinal" comparison, on the other hand, looks purely at the values of the raw byte(s) that represent the character. There's a great sample at http://msdn.microsoft.com/en-us/library/e6883c06.aspx that shows the results of the various StringComparison values. All the way at the end, it shows (excerpted):

StringComparison.InvariantCulture:
LATIN SMALL LETTER I (U+0069) is less than LATIN SMALL LETTER DOTLESS I (U+0131)
LATIN SMALL LETTER I (U+0069) is less than LATIN CAPITAL LETTER I (U+0049)
LATIN SMALL LETTER DOTLESS I (U+0131) is greater than LATIN CAPITAL LETTER I (U+0049)

StringComparison.Ordinal:
LATIN SMALL LETTER I (U+0069) is less than LATIN SMALL LETTER DOTLESS I (U+0131)
LATIN SMALL LETTER I (U+0069) is greater than LATIN CAPITAL LETTER I (U+0049)
LATIN SMALL LETTER DOTLESS I (U+0131) is greater than LATIN CAPITAL LETTER I (U+0049)

您可以看到，在这里InvariantCulture的收益率（U + 0069，U + 0049，U + 00131），序号收益率（U + 0049，U + 0069，U + 00131）。

You can see that where InvariantCulture yields (U+0069, U+0049, U+00131), Ordinal yields (U+0049, U+0069, U+00131).