正如标题所说...:)
As the title says... :)
你能不能帮我建立一个正则表达式匹配不含有字符串AU = 1?
Could you help me to build a regex to match a strings NOT containing "au=1"?
我在玩负向前查找,没有运气,但我敢肯定,我应该使用该得到的东西。
I was playing with negative lookahead with no luck but I'm quite sure that I should get something using that.
谢谢!
我终于用这个正则表达式做了
I finally did it with this regexp
^(?!.*au=1).*$